3x^2-15x+20=3x^2+16-12

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Solution for 3x^2-15x+20=3x^2+16-12 equation: 



3x^2-15x+20=3x^2+16-12

We move all terms to the left:

3x^2-15x+20-(3x^2+16-12)=0

We get rid of parentheses

3x^2-3x^2-15x-16+12+20=0

We add all the numbers together, and all the variables

-15x+16=0

We move all terms containing x to the left, all other terms to the right

-15x=-16

x=-16/-15

x=1+1/15

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